超深數學提. 計時速

sakura s
22t + 80t 大減, 齒比等於6.91
皮帶牙 20t (原裝)
皮帶,原裝522t (原裝)
如果皮帶轉速係1300rpm
咁時速係幾多呢??

首先22齒與80齒的比是1比3.636636363...., 其他資料不全...................

皮帶牙 20t ???皮帶又522t ??? 有咩分別?
皮帶522t  !? 有冇咁多呀?!@@

其實要比個 final gear diff 同 皮帶 gear Ratio

我去3racing個裝佢寫522t炸...我都覺得會唔會多左d...

hinwong 發表於 2011-5-15 23:59

                               
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我去3racing個裝佢寫522t炸...我都覺得會唔會多左d...

522應該係個長度 牙數要／3
計時速應該只關內齒比 大減齒比同rpm

回復 hinwong 的帖子

長皮帶轉一圈 = 前牙差轉    A        圈

A = (長皮帶牙數)/(前牙差牙數=38)

假設走直線來說, 牙差轉速 = 車轆轉速

若  轆直徑 (cm) 計, 皮帶轉速=1300 (round per minute)計

車速  =  (轆直徑 x 3.14 ) x (皮帶轉速1300) x A     {單位系 cm/min }

若車速 以 km/hr 來計, {1cm =1/100 m = 1/100000 km} and  {1minute = 1/60 hr}

車速  = (轆直徑 x 3.14 ) /100000  x (皮帶轉速1300) x A  x 60

數學老師死得早, 唔知有冇錯

Very good, I give you 99.9 marks

Because your answer is the speed on wheel not speed of car

回復 fatchickterian 的帖子

discuss this:
distance of wheel to spin one round = distance of car moved forward?
speed of car = rate of (distance of wheel to spin one round) = rate of (distance of car moved forward)?

果數果然好深...睇完答案都唔明....哈哈

多謝andy兄, 咁有心機教...

回復 hinwong 的帖子

quote Ching alvis425
"522應該係個長度 牙數要／3 "
冇轆在手, 估轆直徑 ~ 5cm

車轆轉一圈所行距離= (5 x 3.14 )/100000 = 0.000157 km
A= (522/3) / 38 ~ 4.58
皮帶轉速 = 1300x 60 =78000 round per hr
車速 = 0.000157 x 4.58 x 78000 ~ 56 km/hr   合理?

地面磨擦呢個factor會唔會需要放埋落條formula度???

回復 buzzybee82 的帖子

冇空轉, o先呔就應該arm.

OzAndy 發表於 2011-5-16 10:54

                               
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回復 hinwong 的帖子

quote Ching alvis425

我估係咁上下掛, 10.5t 加少少turbo

回復 OzAndy 的帖子

I was half joke, but in fact (for more discussion points), have to take in the account of friction losses (as c-hing buzzybee82 suggestion). Not only that, there are also loss due to heat and sound energy too, but be realistic this factors are never clear (e.g. friction factors are different on different surface and temp)!!!!!

回復 hinwong 的帖子

睇其他Ching 點睇, 再discuss 一下

回復 fatchickterian 的帖子

都係大約計下姐....好難超準既, 就算真車, 個錶都未必準...警察影快相都唔準啦...不過多謝ching意見, 等我起馬知道係大約數

OzAndy 發表於 2011-5-16 10:50

                               
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回復 fatchickterian 的帖子
speed of car = rate of (distance of wheel to spin one round) = rate of (distance of car moved forward)?
discuss this:

Not "rate", is the time.

Anyway, you are correct in the calculation.

In fact, I think the speed of the car will be pretty close to the speed of wheel under load and friction.

hinwong 發表於 2011-5-16 11:15

                               
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回復 fatchickterian 的帖子

都係大約計下姐....好難超準既, 就算真車, 個錶都未必準...警察影快相都唔準啦 ...

正常唔會用皮帶計架車既speed 架.

discussion is good for all of us.

回復 keithlaw 的帖子

因為樓主用MT-4 的RPM sensor 測皮帶速 (RPM)
我就測 spur gear (RPM)