You may consider the brushless motor as an ac synchrouous motor with premenant magnet and the three wires as a 3 ph ac source. So, connecting the relay to any 2 out of 3 wires is similar to connecting the relay to a single phase ac source. No idea on the ac voltage. You can simply use a mulit meter to check it and buy an relay with appropriate operating voltage.
The circuit proposed by 艾力 is simple, reliaible and easy to bulid. Very good.
The common nominal current and voltage drop of an LED are around 20mA and 3-3.6v (depends on the color, just assuming it is 3.3v). If you would like to connect the LED to a 7.2V source in series with an resistor, the voltage drop across the resisor is 7.2-3.3 = 3.9V. The value of this resistor is thus equal to 3.9V/20mA = 195 ohm. Say 200 ohm. The power dissipated in the resistor is (20mA)^2 x 200 ohm = 0.08W. So, a 1/4W resistor more than enough.
You may consider connecting 2 LEDs and a 47 ohm 1/4W resistor in serious to the 7.2V source.
原帖由 TT-01 於 2006-9-6 12:22 發表
Please tell me what is coil connector....I've all those article in this subject but hard to understand the theory of brake light...